HomeLatest NewsIPL 2020: Rajasthan Royals Beat Kings XI Punjab By Seven Wickets

IPL 2020: Rajasthan Royals Beat Kings XI Punjab By Seven Wickets

KXIP Had Posted A Target Of 186 Runs For Rajasthan Royals:

In the 50th match of the Indian Premier League ( IPL) 2020 at the Sheikh Zayed Stadium in Abu Dhabi, the Rajasthan Royals (RR) defeated Kings XI Punjab (KXIP) by seven wickets. After this victory, RR remains alive in the ongoing version, after being handed a goal of 186 runs.

Ben Stokes, an English all-rounder, ensured the perfect beginning of the chase, smashing a 26-ball 50. The innings of Stokes consisted of six boundaries and three sixes. Following the English cricketer ‘s dismissal, Sanju Samson kept attacking, scoring a 25-ball 48. The pair got quality support from skipper Steve Smith and Jos Buttler, who, without much ado, helped the side get over the line. A wicket each was accounted for by Murugan Ashwin and Chris Jordan.

For the loss of four wickets, KXIP earlier posted a total of 185 runs. The highest run-scorer was Chris Gayle, smashing 99 runs off 63 deliveries. Six boundaries and eight sixes constituted Gayle’s innings. During his sublime knock, the Windies cricketer further completed 1000 T20 sixes. The pick of the bowlers is England pace-bowler Jofra Archer and Stokes, accounting for two wickets apiece.

Neelam Shaw
Neelam Shawhttps://stumpsandbails.com/
I am a journalist carrying experience in Crime journalism. And I am passionate about cricket which has driven me to pick up Sports reporting and writing. I bring you the latest happening in the cricket world both at National and International level.

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